Hi, John I have a string splited by "\0" ( it means {'\\','0'}, the bellow is the same ), for example: "\0xxxx\0yyyy\0zzzz\0". And there is some special situation like "\0xxx\\0\0yyy\\\0zzz\0" , you can think it is similarly to c style string, the two '\\' means a single '\' and the '\\0' is not a spliter. i want to split them in to 0) xxx\\0 1) yyy\\ c) zzz how can i do it in boost::regex? thx,all

Message: 7 Date: Sat, 26 Apr 2008 12:52:43 +0100 From: "John Maddock" <john@johnmaddock.co.uk> Subject: Re: [Boost-users] a problem about boost::regex To: <boost-users@lists.boost.org> Message-ID: <002d01c8a794$0d593e50$eeea0352@fuji> Content-Type: text/plain; format=flowed; charset="UTF-8"; reply-type=original

Guo Xu wrote:

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a regex expression: (?<=[^\\](?:\\\\)*)\\0 can work well in c#, but error in boost::regex why?

Variable length lookbehind isn't supported in Boost.Regex (or in Perl for that matter).

Regards, John.