Ah, yes, it really works if I explicitly provide the template parameters. What a pity that the extremely beautiful code like f(boost::bind) is not supported! Anyway, it's ok to write something like p<string, string>(boost::bind(f, _1, _2)), which is far better than p(boost::function<void(string,string)>(boost::bind(f, _1, _2)). Thanks for your help! 2012/3/11 Jeffrey Lee Hellrung, Jr. <jeffrey.hellrung@gmail.com>

On Sat, Mar 10, 2012 at 11:56 PM, pwx <airyai@gmail.com> wrote:

...

I tried to create a template function that receives boost::function as parameter. Say like this:

template <typename T1, typename T2> void proc(const boost::function<void(const T1&, T2&)> &p) { // ... }

void f(const string& s1, string&s2) { // ... }

Everything goes ok when I called proc( boost::function<void(const string&, string&)>(f) ). But when I try this:

proc(boost::bind(f, _1, _2));

The compiler refused with the error:

no matching function for call to ‘proc(boost::_bi::bind_t<boost::_bi::unspecified, F, boost::_bi::list2<boost::arg<1>, boost::arg<2> > >)’

Anyway to fulfill this design purpose? Thanks.

Explicitly provide the template parameters? E.g.,

proc< std::string, std::string >(boost::bind(f, _1, _2));

There's really no way for the compiler to figure out what T1 and T2 should be without your help. Or maybe your proc should really be declared like

template< class F > void proc(F const & f);

?

Or maybe you can provide the above overload of proc and have its body provide the explicit template parameters to the original overload of proc for you?

Just some ideas.

- Jeff

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